l = max(1, a - (K - 1)) # b, c の探索範囲の下限 l r = min(N, a + (K - 1)) # b, c の探索範囲の上限 r for b in range(l, r + 1): for c in range(l, r + 1): ...

# このプログラムを N = 1000 で実行すると、正しく 517691607 と出力されます。 # しかし、大きな数の計算を行うのに時間がかかるので、N = 100000 程度でも実行に 1 秒ほどかかります。

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